[VIEWED 5922
TIMES]
|
SAVE! for ease of future access.
|
|
|
OcRam
Please log in to subscribe to OcRam's postings.
Posted on 08-11-08 4:44
PM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
Jamie, Duncan and Ross are talking about their ages. Duncan
realises that his age plus Ross's age is a perfect square. Ross
notices that his age is an exact multiple of the sum of Jamie's
and Duncan's ages. Surprisingly Jamie's age multiplied by Ross's
age is a perfect cube. What are their ages? (1, 1, 8 is not correct answer as 1 year old Duncan can not realise such things)
|
|
|
|
vatguy
Please log in to subscribe to vatguy's postings.
Posted on 08-11-08 5:45
PM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
|
|
|
nepali man6e
Please log in to subscribe to nepali man6e's postings.
Posted on 08-11-08 5:45
PM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
one of the answers might be all three are of same age i.e. 8 For Duncan: D+R= 8+8 = 16 =4*4 For Jamie: J*R= 8*8 = 64 = 4*4*4 For Ross: 16= 1*(8+8) = 16 there might be other answers also, but this answer came first.
|
|
|
vatguy
Please log in to subscribe to vatguy's postings.
Posted on 08-11-08 5:48
PM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
look at that timing dude...
|
|
|
OcRam
Please log in to subscribe to OcRam's postings.
Posted on 08-12-08 8:26
AM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
if answer was to be 8, 8 , 8; in that case, Ross's age can not be exact multiple of sum of Jamie's and Duncan's Age. 8 = (8+8)* Integer ------> Mistake Answer is not right. In fact, there is only one answer if we are to assume that there age is less than 100 and not considering the one I have mentioned in the first question. try if you guys can and if you want.
|
|
|
parbatya
Please log in to subscribe to parbatya's postings.
Posted on 08-12-08 8:39
AM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
Duncan-9
Rose-72
Jamie-3
Last edited: 12-Aug-08 09:16 AM
|
|
|
OcRam
Please log in to subscribe to OcRam's postings.
Posted on 08-12-08 9:17
AM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
Parbatya is wrong. Duncan + Ross is not perfect square.
|
|
|
OcRam
Please log in to subscribe to OcRam's postings.
Posted on 08-12-08 9:19
AM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
Ok, after editing, u got it right. I know u r talented Mr. Parbatya. Right answer by parbatya, that is Duncan 9 Rose 72 Jamie 3 Thank you guys
|
|
|
parbatya
Please log in to subscribe to parbatya's postings.
Posted on 08-12-08 9:19
AM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
How about the new solution?
|
|
|
OcRam
Please log in to subscribe to OcRam's postings.
Posted on 08-12-08 9:20
AM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
|
|
|
nepali man6e
Please log in to subscribe to nepali man6e's postings.
Posted on 08-12-08 11:43
AM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
thanks dude, I really messed up with the multiple and the (prime)factor stuff.
|
|
|
hemu
Please log in to subscribe to hemu's postings.
Posted on 08-12-08 12:21
PM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
Also Check this out:
Duncan = 17
Rose = 64
Jamie = 8
|
|
|
OcRam
Please log in to subscribe to OcRam's postings.
Posted on 08-12-08 12:27
PM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
ROSS = INTEGER* (JAMIE + DUNCAN 64 = INTEGER * (17+8) ---->Mistake
|
|
|
Mr. Hyde
Please log in to subscribe to Mr. Hyde's postings.
Posted on 08-12-08 12:33
PM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
Hemu! To add to OcRam's last equation, Ross age has to be divisible by the sum of Duncan and Jamie ages for your solution to work and still meet the conditions provided in the problem. OcRam! do you have any other such math trivia you wanna put forth?
|
|
|
hemu
Please log in to subscribe to hemu's postings.
Posted on 08-12-08 1:52
PM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
Mr Hyde, OcRam,
I hope if you go through it. It is divisible exactly by 2.56. You might have confused with the decimal number. If you go through it, it is exactly divisible by 2.56.
Ross = z * (Jamie + Duncan)
or 64 = 2.56 * (8 + 17)
explore it............
Last edited: 12-Aug-08 02:01 PM
|
|
|
hemu
Please log in to subscribe to hemu's postings.
Posted on 08-12-08 1:52
PM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
OcRam ,
The question has not mentioned about integer.
so ,
Ross = y * ( Jamie + Duncan)
or, 64 = 2.56 *(8 + 17)
Check this out. Rather then going traditional try exploring.
Last edited: 12-Aug-08 01:52 PM
Last edited: 12-Aug-08 01:58 PM
|
|
|
hemu
Please log in to subscribe to hemu's postings.
Posted on 08-12-08 1:52
PM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
Last edited: 12-Aug-08 01:53 PM
|
|
|
OcRam
Please log in to subscribe to OcRam's postings.
Posted on 08-12-08 2:22
PM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
exact multiple. come on, that's basic....
|
|
|
Mr. Hyde
Please log in to subscribe to Mr. Hyde's postings.
Posted on 08-12-08 2:30
PM
Reply
[Subscribe]
|
Login in to Rate this Post:
0
?
|
|
That's what happens when a wanna-be lawyer tries to solve a basic mathematical problem. In Math, when you say 'x'(dividend) is divisible by 'y'(divisor), it leaves no remainder and the quotient is an integer.
|
|